Question

A car of mass 1200 kg is moving with a velocity of 72 km/h when breaks are applied it stops after 52 sec calculate the force

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\large\red{\boxed{\sf Force(F)=-461N }}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Mass (m) = 1200kg

• Velocity (u) = 72km/h

In m/s $\large\implies{u=72×\frac{5}{18}}$

$\large\implies{\sf u=20m/s}$

• Time (t) = 52 sec

$\large\underline\pink{\sf To\:Find: }$

• Force applied to stop the car (F)=?

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We know that ,

$\LARGE{♡}$$\large{\boxed{\sf Acceleration (a)=\frac{v-u}{t}}}$

$\large\implies{\sf a=\frac{0-20}{52} }$

$\Large\implies{\sf a=-0.38m/s^2}$

Now ,

$\LARGE{♡}$$\large{\boxed{\sf Force(F)=ma }}$

$\large\implies{\sf F=1200×-0.38 }$

$\large\implies{\sf F=-461N}$

$\huge\red{♡}$$\Large\red{\boxed{\sf Force(F)=-461N }}$

Hence ,

Force applied to stop the car is -461N