Question

A car of mass 1200 kg negotiates a banked curve of radius 120 m on a smooth road. If the banking angle is 37°, the speed of the car for safe turn is​

Answer 1

Step by step explanation:

Given: The mass of the car is $1200 kg$, the curve of the radius is $120m$ and the baking angle is $37$°

To find: The speed of the car for the safe turn.

For calculation of speed of the car,

We know that $Tan$Ф$= \frac{v^{2} }{rg}$  and $Tan$Ф $= 37$°

⇒ $Tan37$°$= \frac{v^{2} }{120x10}$

The value of $Tan37= 0.75$

Thus,

⇒ $0.75=\frac{v^{2} }{1200}$

⇒ $0.75$ × $1200 = v^{2}$

⇒ $900=v^{2}$

Thus, $v=\sqrt{900}$

⇒$v=30ms^{-1}$

The speed of the car for the safe turn is $30ms^{-1}$.