Question

a car of mass 1200kg is moving with a constant speed of 36km/h. find the netforce acting on the car?

Answer 1

Explanation:

Given,

mass = 1200 kg

speed = 36 km/h = 10 m/s

initial velocity, u = 0 m/s

final velocity, v = 10 m/s

acceleration, a = ?

according to the third eqn of motion,

v^2 - u^2 = 2as

10^2 - 0^2 = 2×a×10

100 = 20a

a = 5 m/s^2

we know that,

F = ma

F = 1200 × 5

F = 6000 N or 6000 kg/m\s^2

Answer 2

Question :–

A car of mass 1200kg is moving with a constant speed of 36km/h. find the netforce acting on the car ?

Given :–

1. Mass = 1200 kg
2. u = $\cancel{36} \times \frac{10 \cancel{00}}{\cancel{36} \cancel{00}} m/s = 10 m/s$

To Find :–

• Find the net force acting on the car.

Solution :–

v = 0 m/s & s = 20 m

$\boxed{ \sf \red{{v}^{2} - {u}^{2} = 2as}}$

$\implies 0 - {(10)}^{2} = 2a(20)$

$\implies -100 = 2a(20)$

$\implies \frac{ \cancel{-10} \cancel{0}}{\cancel{2} \cancel{0}} = 2a$

$\implies -5 = 2a$

$\implies \frac{-5}{2} = a$

Therefore,

$\boxed{ \sf \red {a = -2.5 {m/s}^{2}}}$

We know that,

$\boxed{ \sf \red{ F = ma}}$

F = 1200 × (-2.5)

F = -3000N

Hence,

The net force acting on the car is 3000N.