A car of mass 1250 Kg is moving at a uniform speed of 72 Kmph. On
applying brakes its speed is reduced to 18 Kmph. Calculate the work done on the car.
Answers
Answered by
0
Explanation:
Factor Theorem
In mathematics, factor theorem is used when factoring the polynomials completely. It is a theorem that links factors and zeros of the polynomial.
According to factor theorem, if f(x) is a polynomial of degree n ≥ 1 and ‘a’ is any real number, then, (x-a) is a factor of f(x), if f(a)=0.
Answered by
0
m = 1250kg
u = 72km/h = 20m/s
v = 18km/h = 5m/s
Initial kinetic energy = 1/2mu^2
= 1/2(1250)(20)^2 = 250000J
Final kinetic energy = 1/2mv^2
= 1/2(1250)(5)^2 = 15625J
Change in Kinetic Energy = Final kinetic energy - Initial kinetic energy
= 1/2mv^2-1/2mu^2
= 15625-250000
= -234375J
Similar questions