A car of mass 1250 kg is moving at a uniform speed of 72 km/h. On applying brakes it's
speed is reduced to 18 km/hr . Calculate
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Answer:
m = 1250kg
u = 72km/h = 20m/s
v = 18km/h = 5m/s
Initial kinetic energy = 1/2mu^2
= 1/2(1250)(20)^2 = 250000J
Final kinetic energy = 1/2mv^2
= 1/2(1250)(5)^2 = 15625J
Change in Kinetic Energy = Final kinetic energy - Initial kinetic energy
= 1/2mv^2-1/2mu^2
= 15625-250000
= -234375J
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