Question

a car of mass 1400 kg brought to rest from a speed of 50m/s by constant braking force of 6000N caluclate retardation.​

Answer 1

Answer:

Step-by-step explanation:

Given,

Mass of car, M=2000kg

Velocity, V=72×  

18

5

​

=20ms  

−1

 

Apply kinematic equation of motion

v  

2

−u  

2

=2as

0−20  

2

=2a×20

a=−10ms  

−2

 

Breaking force, F=ma=2000×10=20 kN

Apply first kinematic equation

v=u+at

t=  

a

v−u

​

=  

−10

0−20

​

=2 sec

Breaking force is 20 kNand time is 2sec.

Answer 2

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