Question

A car of mass 1400kg increases it's velocity from 36 km/hr, to
70 km/hr calculate the work done by the engine.
​

Answer 1

Explanation:

Initial Velocity, u=54km/hr=15m/s

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/s

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kg

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 2

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 2

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 21

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 21

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 21 1500×15×15=168750J

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 21 1500×15×15=168750JFinal kinetic energy

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 21 1500×15×15=168750JFinal kinetic energy 2

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 21 1500×15×15=168750JFinal kinetic energy 21

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 21 1500×15×15=168750JFinal kinetic energy 21

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 21 1500×15×15=168750JFinal kinetic energy 21 mv

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 21 1500×15×15=168750JFinal kinetic energy 21 mv 2

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 21 1500×15×15=168750JFinal kinetic energy 21 mv 2

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 21 1500×15×15=168750JFinal kinetic energy 21 mv 2 ⇒

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 21 1500×15×15=168750JFinal kinetic energy 21 mv 2 ⇒ 2

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 21 1500×15×15=168750JFinal kinetic energy 21 mv 2 ⇒ 21

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 21 1500×15×15=168750JFinal kinetic energy 21 mv 2 ⇒ 21

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 21 1500×15×15=168750JFinal kinetic energy 21 mv 2 ⇒ 21 1500×20×20=300000J

Initial Velocity, u=54km/hr=15m/sFinal velocity , v=72km/hr=20m/sMass =1500kgInitial kinetic energy 21 mu 2 ⇒ 21 1500×15×15=168750JFinal kinetic energy 21 mv 2 ⇒ 21 1500×20×20=300000JSo, change in kinetic energy = work done=300000−168750=131250J

Answer 2

Answer:

194660.5 Joules

Explanation:

By Work-energy Theorem

Change in Kinetic Energy= Work Done

$0.5 m( {v}^{2} - {u}^{2} )$

here,

• u = 36km/hr = 10 m/s,.
• v = 70km/hr = (175/9) m/s. and
• m=1400kg

Therefore,

W=

$0.5 \times 1400 \times ( {(175 \div 9)}^{2} - 100)$

=194660.5 Joules

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