a car of mass 150 kg is moving om a level road with a velocity of 52 km/hr. Find the work don in stopping the car.
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Question : A car of mass 150 kg is moving om a level road with a velocity of 52 km/hr. Find the work don in stopping the car.
Solution : Given in the question,
Mass = 150 kg.
Velocity (initial) = 52 Km/hr ⇒ 52 × 1000 m / 60 × 60 sec = 14.44 m/s.
(Final velocity = 0)
Work done = Change in kinetic energy.
Therefore, Work done = Initial K.E. - Final K.E.
⇒ Work done = i K.E. - f K.E. ⇒ 1/2 m (vi² - vf²)
⇒ Work done = 1/2 × 150 × {(14.44)² - (0)²}
After solving we got,
⇒ Work done = 15638 Joules. (approximately).
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