Question

A car of mass 150 kg was pushed by two members with a net force 200N for 4Seconds. What is the change in the velocity of car?

Answer 1

Given:

A car of mass 150 kg was pushed by two members with a net force 200N for 4Seconds.

To find:

Change in velocity of car?

Calculation:

Let acceleration be 'a':

$\rm \: a = \dfrac{force}{mass}$

$\rm \implies\: a = \dfrac{200}{150}$

$\rm \implies\: a = 1.33 \: m {s}^{ - 2}$

Now, applying 1st equation of kinematics:

$\rm \: v = u + at$

$\rm \implies \: v - u = at$

$\rm \implies \: \Delta v = at$

$\rm \implies \: \Delta v = 1.33 \times 4$

$\rm \implies \: \Delta v = 5.32 \: m {s}^{ - 1}$

So, change in velocity is 5.32 m/s.

Answer 2

HELLO DEAR,

GIVEN:- A car of mass 150 kg was pushed by two members with a net force 200N for 4Seconds. What is the change in the velocity of car?

SOLUTION:- Mass of car (m) = 150 Kg

Force applied by the two members on the car (F) = 200 N.

Net time till the force applied on the car (t) = 4 seconds.

Let the change in velocity of car due to above operation = Δv

F = ma

a = F/m

a = 200/150

a = 1.33 m/s²

Using equation of kinematics,

v= u+at

v-u = at ( final velocity (v) - intial velocity (u) = change in velocity Δv )

Δv = at

putting the value of a = 1.33 m/s² and t = 4 s.

Δv = 1.33 × 4

Δv = 5.32 m/s

THANKS.