A car of mass 1500 kg is moving with a speed of 12.5m/s on a circular path of radius 20m on a level road.What should be the frictional force between ? What should be the value of the coefficient of friction to attain this force?
Answers
Answered by
1
Answer:
1.172×104N ; 0.8
Explanation:
Here, m=1500kg,υ=12.5m/s,r=20m
Frictional force = required centripetal force
f=mυ2r=1500×12.5×12.520=1.172×104N
μ=fR=fmg=1.172×1041500×9.8=0.8
Similar questions