A car of mass 1500 kg, is ruunning
at a speed of 50 Km per hour. When breaks are applied .It comes to rest after covering a distance of 25 m. calculate thr force applied by the breaks of the car
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Answer:
Given mass of car =1000kg
u=speed=90km/hr=90×185m/sec
u=25m/sec
it have to stop in 5sec
then final velocity =0
⇒v=u+at
o=25+a×5
=a=−5m/sec2
then the force applied by break is ma
=1000X−(5m/sec2)
=−5000M
force =5000N by break
distance travelled to stop the car after break is applied (s=distance)
v2=u2+2as
0=(25)2−2×5×s
=s=10(25)2=62.5m
work done by break =F×s
w=5000×62.5=312.5KJ
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