Question

A car of mass 1500 kg moving with a velocity 54 km/h collides head on with the brick wall and immediately comes to rest. The magnitude of change in the momentum of the car is

Answer 1

54km/hr=15m/s

change in momentum=m(v-u)

=1500(0-15)

=1500 x -15 =-22500kgm/s

Answer 2

Answer:

The magnitude of change in the momentum of the car is 22.5×10³ Kgm/s.

Explanation:

We have given, the mass of the car, m = 1500kg

The initial velocity of the car, u = 54Km/h

After the head on collision of the car with brick wall. It comes to rest.

Final velocity of the car will be, v = 0

We know the formula of the momentum:

Momentum = mass × velocity

Initial momentum of the car = mu = (1500)(54) = 81000 kgkm/h

Final momentum of the car = mv = 0

Therefore, change in the momentum of the car $= mv - mu$

The change in the momentum =$0 - 81000$

The change in the momentum $=-81*10^3kg\;km/h = -22.5*10^3 \;kgms^{-1}$

As we know that the momentum is directly proportional to the force applied. The negative sign shows that the force applied in the opposite direction to the initial velocity of the car.

Click here to know about "Linear Momentum"

https://brainly.in/question/4765800

Click here to know about "Conservation of momentum"

https://brainly.in/question/14777335