Question

A car of mass 1500 kg moving with a velocity 54 km/h collides head on with the brick wall and immediately comes to rest. The magnitude of change in the momentum of the car is

Answer 1

ch. in momentum is mv-mu
=1500×15-1500×0
=22500-0
=22500kg ms^1

Answer 2

$\huge\underline\mathfrak\red{ANSWER}$

WHAT IS MOMENTUM?

LET START OUR JOURNEY WITH A INTERESTING FACT WHICH IS HARDY KNOW BY OTHERS...[{}]

NOW GIVE THE ANSWER WHICH OF THE FOLLOWING WILL REQUIRED GREATER FORCE.

A BULLET, OR A TRUCK.....

YOU GET SHOCKED THAT BOTH WILL REQUIRED SAME AMOUNT OF FORCE SO WHEN SCIENTISTS COME TO KNOW ABOUT IT THAN THEY ARE INTUTIVE TO COMBINE THE MASS OR VELOCITY OF THE GIVEN BODY THAN THIS TERM TOSSED NAMELY MOMENTUM....[℅]

$mass = 1500kg \\ u(initial \: velocity) = 54km {h}^{ - 1} \\ v(final \: velocity) = 0 \\ \\ initial \: momentum = mu \\ final \: momentum = mv \\ \\ change = final - initial \\ \\ change \: in \: momentum = mv - mu \\ \\ change \: in \: momentum = 1500(0) - 1500(54) \\ \\ change \: in \: momentum = - 81000$

WHAT THIS NEGATIVE SIGN IMPLIES ?

AS WE KNOW FROM NEWTON'S SECOND LAW OF MOTION THAT CHANGE IN MOMENTUM IS DIRECTLY PROPORTIONAL TO THE FORCE APPLIED NOW READ YOU QUESTION WHICH IMPLIESES THAT THE CAR AFTER COLLISION AQUIRE ZERO VELOCITY IT MEANS FORCE IS APPLIED IN OPPOSITE DIRECTION TO THAT OF INITIAL VELOCITY NEGATIVE SIGN HERE IMPLIESES THIS OPPOSITE DIRECTION OF FORCE...

ANSWER BY....

PURPLE WORLD

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