Question

A car of mass 1500 kg starting from rest can reach a speed of 20
m/s within 10 seconds. Calculate the accelerating force of the car
engine.​

Answer 1

Given :

• Mass of car, m = 1500 kg
• Initial velocity, u = 0 m/s (starting from rest)
• Final velocity, v = 20 m/s
• Time taken, t = 10 seconds

To find :

• Acceleration, a &
• Force, F

According to the question,

➞ v = u + at [First equation of motion]

Where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time taken

➞ Substituting the values,

➞ 20 = 0 + a × 10

➞ 20 - 0 = 10a

➞ 20 = 10a

➞ 20 ÷ 10 = a

➞ 2 = a

• So,the acceleration is 2 m/s².

Now,

➞ Force = Mass × Acceleration

Or,

➞ F = ma

➞ F = 1500 × 2

➞ F = 3000 N

• So, the force of the car engine is 3000 Newton.

Answer 2

Answer:

Given :-

• Mass = 1500 kg
• Initial velocity = 0 m/s
• Final velocity = 20 m/s
• Time taken = 10 sec

To Find :-

Force applied

Solution :-

Firstly we will find Acceleration by using first equation

$\bf \: v \: = u + at$

$\tt \: 20 = 0 + (a)(10)$

$\tt \: 20 = 0 + 10a$

$\tt \: 20 = 10a$

$\tt \: a \: = \dfrac{20}{10}$

$\tt \: a \: = 2 \: {ms}^{ - 1}$

Hence :-

Acceleration of car is 2 m/s

Now,

Let's find Force applied

$\huge \bf \: F = ma$

Here,

F is the Force

M is the Mass

A is the Acceleration

$\tt \: F =1500 \times 2$

$\bf \boxed{ \bf \: F = 3000 \: N}$