Question

A car of mass 1500 kg takes a turn of a curved road of radius 300m with a speed of 9 m/s. The centripetal
force acting on the car is

Options:

a) 45N
b) 225N
c) 810N
d) 405N​

Answer 1

Given:-

• Mass of Car = 1500kg

• Radius of Road = 300m.

• Initial Velocity of Car = 9m/s.

To Find:-

• The Centripetal force acting on body.

Formulae used:-

• Centripetal force = $\rm{\dfrac{mv^2}{r}}}}$

Now,

→ $\implies\rm{ Centripetal\:force = {\dfrac{mv^2}{r}}}$

→ $\implies\sf{ F = \dfrac{ 1500\times{(9)^2}}{300}}$

→ $\implies\sf{ F = \dfrac{1500\times{81}}{300}}$

→ $\implies\sf{ F = \dfrac{121500}{300}}$

→ $\implies\sf{ F = 405N}$

Hence The Centripetal force acting on the car is 405N.

Answer 2

Answer:

• Mass of the Car = 1500 kg
• Radius of Road = 300 m
• Velocity of the Car = 9 m/s.
• Centripetal Force acting on the Car = ?

⠀

$\underline{\bigstar\:\textsf{According to the given Question :}}$

$:\implies\sf Centripetal\:Force=\dfrac{Mass \times (Velocity)^2}{Radius} \\ \\ \\:\implies\sf Centripetal\:Force = \dfrac{mv^2}{r}\\\\\\:\implies\sf F = \dfrac{1500\times (9)^2}{300}\\\\\\:\implies\sf F = \dfrac{1500\times81}{300}\\\\\\:\implies\sf F=5\times81\\\\\\:\implies\underline{\boxed{\sf F=405\:N}}$

⠀

$\therefore\:\underline{\textsf{Centripetal Force acting on Car is of D) \textbf{405 N}}}$