Question

a car of mass 1500kg travelling at 10m/s2 is brought to rest in 5s CALCULATE average acceleration ,average breaking force, total distance covered before coming to rest

Answer 1

Average acceleration = (v - u) / t
= (0 m/s - 10 m/s) / 5 s
= - 2 m/s²
[Negative sign indicates that average acceleration is in the direction opposite to the the motion of car]

Average breaking force = mass × Average acceleration
= 1500 kg × (-2 m/s²)
= -3000 N
[Negative sign indicates that breaking force is in the direction opposite to the the motion of car]

Total distance covered = (v² - u²) / (2a)
= [(0 m/s)² - (10 m/s)²] / (2 × (-2 m/s²))
= 2.5 m