A car of mass 1800 kg moving with a speed of 10 M per second is brought to rest after covering a distance of 50 M calculate the force acting on the car
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m=1800kg
u=10m/s
v=0m/s
s=50m
using second equation of motion
2as=(v*v)-(u*u)
2*a*50=0-100
a=-2
F=m*a
1800*2
- 3600 N
negative sign shows opposite direction of force and motion
u=10m/s
v=0m/s
s=50m
using second equation of motion
2as=(v*v)-(u*u)
2*a*50=0-100
a=-2
F=m*a
1800*2
- 3600 N
negative sign shows opposite direction of force and motion
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