Question

A car of mass 1800 kG moving with a speed of 10m/s is brought to rest after covering a distance of 50m calculate the force applied to the car​

Answer 1

Answer:

Correct option is A)

Given,

M=1800kg

u=10ms -¹

s=50m

F=?

We know that

V ² −u ² =2as

=0−(10)² =2a×50m

a= 100/−100

=−1ms -²

F=ma

Therefore, deceleration=−1m/s ²

Deceleration=−(acceleration)

F=1800×1ms −2=1800N

Force will be acting in the opposite direction to a displacement of the car

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