Question

A car of mass 2, 000 Kg travelling with a uniform velocity of 2 m/s accelerates till its velocity becomes 22 m/s. The work done on the car is:

Answer 1

First law of motion v=u+at
                    v = 22m/s   u = 2m/s   t =1s (as it is travelling with uniform velocity which means same velocity in equal interval of time i.e. 1s)
                    
                         a = v-u = 20m/s^2
  As mass = 2000 kg     force F = ma = 2000(20) =40000N
     work done by the body ,W = F.s 
       from third law of motion   v2 −u2 = 2as
484 −4 = 40s  
s = 48040=12m
W = F.s = 40000(12) = 480000 joule.
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