A car of mass 2 * 103 kg travelling at 36 km/hr on a horizontal road is brought to rest in a distance of 50m by the action of brakes and frictional forces.
Calculate: (a) average stopping force, (b) Time taken to stop the car.
Answers
Answered by
4
Answer:
a)360N
b)100sec
Explanation:
apply kinematics equations
v²=u²+2as
as the is already in motion our initial velocity u = 36km/hr
converting this to the si units gives 18m/s
use the below conversion(18km/hr =5m/s)
v²-u²=2as
0-18m/s = 2 x a x 50m
a = -18m/s ÷ (50m x 2)
a = 0.18m/s²
F = ma
= 2000kg x 0.18m/s²
=360N
time use
v = u + at
t = (v-u)÷a
= (0-18m/s)÷-0.18m/s²
= 100sec
Answered by
0
Answer:
https://www.youtube.com/watch?v=glDU96h8A48
Explanation:
28:46
Similar questions