Question

A car of mass 2.5 tones moves on a level road under the action of 12 kN propelling force . find the time taken by the car to increase its velocity from 36km.p.h to 54km.p.h​

Answer 1

Answer:

ᴿᴱᶠᴱᴿ ᵀᴴᴱ ᴬᵀᵀᴬᶜᴴᴹᴱᴺᵀ

ᴴᴼᴾᴱ ᴵᵀ ᴴᴱᴸᴾˢ◉‿◉

Answer 2

Given,

Mass of a car = 2.5 tonnes

Propelling force acting on the car = 12 kN

To find,

The time taken by the car to increase its velocity from 36km.p.h to 54km.p.h.

Solution,

We can simply solve this numerical problem by using the following process:

Mathematically,

Force acting on an object = mass of the object × acceleration produced

=> acceleration produced = Force acting on an object/mass of the object

{Statement-1}

Also, acceleration = (change in velocity)/time taken

=> time taken = (change in velocity)/acceleration

{Statement-2}

Now, according to the question;

Acceleration of the car

= Force acting on an object/mass of the object

(according to statement-1)

= 12 kN/2.5 tonnes

= 12000 N/250 Kg

= 48 m/s^2

Now, according to the statement-2;

The time taken by the car to increase its velocity from 36km.p.h to 54km.p.h.

= (change in velocity)/acceleration

= (54km.p.h. - 36km.p.h)/48 m/s^2

= 18 km.p.h./48 m/s^2

= (5 m/s)/48 m/s^2

= 0.1 seconds

Hence, the time taken by the car to increase its velocity from 36km.p.h to 54km.p.h is approximately equal to 0.1 seconds.