Question

a car of mass 200 kg moves with an initial speed of 72 kilometre per hour if on applying brakes a constant acceleration of 0.2 metre per second square is produced the distance covered by the car before it stop would be​

Answer 1

Answer:

bhai physics mara samaj ma nahi aata

Explanation:

so, sorry bhai

Answer 2

Answer:

The distance covered by the car before it stop would be​ $10km.$

Explanation:

We are given that

$m=200kg$

Initial speed $u=72km/h$

Converting it to meter per second

$u=72=5/18$

$u=20m/s$

Also,

$v=0$

$a=0.2m/s^{2}$

We will use third equation of motion here

$v^{2} -u^{2} =2as$

Using values,

$0 -20^{2} =2*0.2*s$

$400/0.04=s$

$s=100*100=10km$

The distance covered by the car before it stop would be​ $10km.$

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