A car of mass 2000 kg changes its speed from 72 km/h to 36 km/h in 5 seconds.the force applied by its brake is
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Answered by
15
Given,
- A Car of Mass(m) - 2000 kg
- Initial Velocity of Car(u) - 72km/h
- Final Velocity of Car (v) - 36km/h
║Change km\h into m\s ║
To Find,
- The Force Applied by its brake .
Solution :
We Know First Equation of Motion :
Now Put the Value in this Equation :
Therefore,
There is a Retardation of 2 m/s² due to Force applied by break.
Now We Find Force,
Therefore,
The Force Applied by its brake is 4000N.
(Negative Sign Show the Opposite Direction)
Answered by
11
Answer :
Given -
- Mass = 2000 kg
- Speed changes from 72 km/hr to 36 km/hr
- Time = 5 seconds
To Find -
- Force applied by the brake ?
Solution -
Converting the speed given :
- 72 * 5/18 = 20 m/s
- 36 * 5/18 = 10 m/s
Finding acceleration : (v - u)/t
⇒ a = (10 - 20)/5
⇒ a = -10/5
⇒ a = -2 m/s²
Now, Force = Mass * Acceleration
➸ F = 2000 * -2
➸ F = -4000 N
Therefore, Force applied by the brakes on the car is 4000 N in the opposite direction.
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