A car of mass 2000 kg is moving with a speed of 15m/s on a circular path of radius 20 m on a level road. What will be the frictional force between the car and the road so that car may bot slip? Also find the value of coefficient of friction to attain this force .
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Answer:
Given : Radius of the circular path r=20 m
Mass of the car M=1500kg
Speed v=12.5 m/s
Let the coefficient of friction be μ.
The centrifugal force will balance the friction force so that the car does not slip.
∴ rmv2=μmg ⟹ μ=rgv2
μ=20×9.8(12.5)2=0.8
Explanation:
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