Question

A car of mass 2000 kg rounds a curve of radius 250 m at 90 km/hr. Compute its,(a) Angular speed(b) Centripetal acceleration(c) Centripetal force.(Ans : 0.1 radian's, 2.5 m/s², 5000 N)

Answer 1

veloctiy = Radius* Angular Velocity

velocity=90*5/18 m/s

velocity=25 m/s

angular velocity = velocity/radius=25/250=0.1 rad/s

centripetal acceleration = angular velocity ^2 * radius = 0.01 *250 =2.5 m/s^2

centripetal force = m* centripetal acceleration = 2000*2.5 =5000 N

Answer 2

ASSALAMUALAIKUM,

GIVEN VALUES:- M = 2000Kg ; R = 250m;

V = 90 km/ hr

NOTE :- ( v is in km/hr, we have to convert it in m/s.)

hence, V = 90* 5 / 18

V = 25m/s

(a) ANGULAR VELOCITY = VELOCITY / RADIUS

= 25 / 250

=0.1 rad/sec.

(b) CENTRIPETAL ACCELERATION

= V^/ R

= 25*25 / 250

=2.5m/s^

(c) CENTRIPETAL FORCE:-

= MV^/R

= 2000*25*25/250

=5000N

INSHAALLAH it will help you!