Question

a car of mass 2000kg moving with a velocity of 50 kmph collids with a tree and comes to rest in 5 seconds .what will be the force exerted by the car on the tree​

Answer 1

Answer:

Given,

Mass of car, M=2000kg

Velocity, V=72×

18

5

=20ms

−1

Apply kinematic equation of motion

v

2

−u

2

=2as

0−20

2

=2a×20

a=−10ms

−2

Breaking force, F=ma=2000×10=20 kN

Apply first kinematic equation

v=u+at

t=

a

v−u

=

−10

0−20

=2 sec

Breaking force is 20 kNand time is 2sec.

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Answer 2

GIVEN :

• Mass of a car = 2000 kg.
• Velocity of a car = 50 km/hr = 14 m/s.
• Time = 5 seconds.

TO FIND :

• The force exerted by the car on the tree.

FORMULAS REQUIRED :

• $\tt F \ = \ m \times \dfrac {v-u}{t}$

SOLUTION :

To find the force exerted by the car on the tree = ?

We know that,

$\large {\tt Force \ = \ mass \times acceleration}$

$\qquad \qquad \large \red {\boxed {\tt Force \ = \ m \times \dfrac {v - u}{t}}}$

$\qquad \implies {\tt Force \ = \ 2000 \times \dfrac {0 - 14}{5}}$

$\qquad \implies {\tt Force \ = \ - 400 \times 14}$

$\qquad \qquad \large \blue {\boxed {\tt F \ = - 5600 \ N}}$

•°• The force exerted by the car on the tree is - 5600 Newton.