A car of mass 200kg moving at 36km/hr is brought to rest after it covered a distance of 10m. Find the retarding force acting on the car
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converting speed into m/s = 36×5/18=10m/s
0-10×10=2a×10
-100=20a
a=-100/20
a=-5m/s^2
Retarding force = ma
F=200×5
F=1000N
negative sign is removed as it is already mentioned that force is retarding.
0-10×10=2a×10
-100=20a
a=-100/20
a=-5m/s^2
Retarding force = ma
F=200×5
F=1000N
negative sign is removed as it is already mentioned that force is retarding.
Answered by
1
0-10×10=2a×10
-100=20a
a=-100/20
a=-5m/s^2
Retarding force = ma
F=200×5
F=1000N
negative sign is removed as it is already mentioned that force is retarding
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