A car of mass 2400 kg moving with a velocity of 20 m/s is stopped in 10 seconds on applying brakes. Calculate the retarding force
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Answered by
3
u=20m/s
m=2400kg
t=10s
v=0
a=v-u/t
a= 0-20/10=-2m/s^2
force =m×a
= 2400×2=4800N
m=2400kg
t=10s
v=0
a=v-u/t
a= 0-20/10=-2m/s^2
force =m×a
= 2400×2=4800N
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Answered by
5
HEYA!
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Mass = 2400kg
Initial velocity u = 20m/s
Final velocity v = 0
Time = 10 seconds .
Using the first equation of motion
V= U + AT
0 = 20 + 10 A
10 A = -20
A = -2 m/s2.
Now regarding force ,
F = ma
F= 2400× -2
= -4800N
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Mass = 2400kg
Initial velocity u = 20m/s
Final velocity v = 0
Time = 10 seconds .
Using the first equation of motion
V= U + AT
0 = 20 + 10 A
10 A = -20
A = -2 m/s2.
Now regarding force ,
F = ma
F= 2400× -2
= -4800N
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