A car of mass 2400 kg moving with a velocity of 20 m/s is stopped in 10 seconds on applying brakes. calculate the retardation and the regarding force.
can anybody please answer the questions there??
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3
Solution 4 :- m=2400 kg
u, initial velocity = 20 m/s
v, final velocity = 0
t = 10 second
a = v - u/t = -2 m/s² (Minus sign showing retardation)
F = m×a
= 2400× -2 N
= -4800 N AnsWer
u, initial velocity = 20 m/s
v, final velocity = 0
t = 10 second
a = v - u/t = -2 m/s² (Minus sign showing retardation)
F = m×a
= 2400× -2 N
= -4800 N AnsWer
adhil92:
I have a doubt, the -4800 is the regarding force
am I right
Yeah minus sign shows opposite direction
can u make it fast bro
please
please ask your question again because I can't edit my answer to help you
ok
I asked it again
OK let me see
please make it a bit fast
Answered by
2
acceleration is equal to (V-u) / t
so a = (0-20)/10=-2mper sec square is the retardind acceleration.
force = m into acceleration
f =2400*-2=4800N .
so a = (0-20)/10=-2mper sec square is the retardind acceleration.
force = m into acceleration
f =2400*-2=4800N .
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