A car of mass 2500 kg moving with a velocity 10 m / sec brought to rest in 5 sec by applying brakes.Find the retarding force produced by the brakes.
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Answer:-
Given:-
- Initial velocity (u) = 10 m/s
- Final velocity (v) = 0 m/s [Since it will come on rest]
- Mass (m) = 2500 kg
- Time taken (t) = 5 s
To Find:-
Regarding force (F) produced by the brakes.
_____________...
Finding acceleration:-
We know,
a = (v-u)/t
or, a = -u/t
where,
- a = Acceleration,
- v = Final velocity,
- u = Initial velocity &
- t = Time.
So,
a = - (10 m/s)/5s
➵ a = (-10 m/s)/5s
➵ a = -2 m/s² ...(Acceleration)
Finding retardation force:-
We know,
F = ma
where,
- F = Force,
- m = Mass &
- a = Acceleration.
∴ F = (2500 kg) (-2 m/s²)
➵ F = - 5000 kg m s^-2
➵ F = - 5000 N ...(Force against motion)
Therefore, the retarding force was (-5000 N) against the path of motion.
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