Question

A car of mass 2500kg accelerate at the rate of 4ms^-2 and then at the rate of 16ms^-2 calculate the ratio of the force exerted by the engine in the two cases

Answer 1

Answer: 1:4

Explanation:we know that

F=ma

F¹= 2500×4

=10000N

F²= 2500×16

=40000N

F¹:F² = 10000:40000

=1:4