Question

A car of mass 2500kg accelerates at the rate of 4m/s2 and then at the rate of 16m/s2.calculate the ratio of the Forces exerted by the engine in the two cases?

Answer 1

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F= ?
M= 2500
A= 4m/s^2 & 16m/s^2

Apply formula, F= m×a
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F^1= 2500 × 4 => 10000
F^2= 2500 × 16 => 40000

F=> 10000/40000
=> 1/4...Ans..✔