Question

a car of mass 2kg initial velocity of 10m/s and final velocity 20m/s find change in kinetic energy

Answer 1

Mass of the car =2kg.
Velocity of the car=10m/s.
kinetic energy=$\frac {1/2mv^2}$=1/2×2kg×10×10=100kgm/s^2
Final velocity =20m/sec
Kinetic energy =1/2mv^2=1/2×2kg×20×20=400kgm/s^2

Change in kinetic energy =400-100kgm/s^2=300kgm/s^2

Answer 2

In this question,

Mass = 2 kg

Initial velocity = 10 m/s

Final Velocity = 20 m/s

Kinetic Energy = 1/2 m(v2^2-v1^2)

$= > k = \frac{1}{2} \times 2( v_{2}^{2} - v_{1}^{2} )$

$= > k = \frac{1}{2} \times 2(400 - 100)$

$= > k = \frac{1}{2} \times 2 \times 300$

$= > k \: = 300 \: joules \:$



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