Question

A car of mass 300 kg moving with a velocity of 60 km/h collides with another small car B of mass 150 Kg.If both the cars stop on colliding, then car B was moving with a speed of​

Answer 1

Explanation:

Using Momentum Conservation:

⇒m

1

u

1

+m

2

u

2

=m

1

v

1

+m

2

v

2

⇒1(21)+2(−4)=1(1)+2v

2

⇒v

2

=6m/s

Coefficient of Restitution:

e=

u

1

−u

2

v

2

−v

1

=

21+4

6−1

=0.2

Kinetic Energy lost:

=

2

1

m

1

(v

1

2

−u

1

2

)+

2

1

m

2

(v

2

2

−u

2

2

)

=

2

1

1(1−441)+

2

1

2(36−16)

=−200J

Impulse of Force:

I=(Δmv)

1

=1(1−21)=−20

=(Δmv)

2

=2(6−(−4))=20