A car of mass 300 kg moving with a velocity of 60 km/h collides with another small car B of mass 150 Kg.If both the cars stop on colliding, then car B was moving with a speed of
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Explanation:
Using Momentum Conservation:
⇒m
1
u
1
+m
2
u
2
=m
1
v
1
+m
2
v
2
⇒1(21)+2(−4)=1(1)+2v
2
⇒v
2
=6m/s
Coefficient of Restitution:
e=
u
1
−u
2
v
2
−v
1
=
21+4
6−1
=0.2
Kinetic Energy lost:
=
2
1
m
1
(v
1
2
−u
1
2
)+
2
1
m
2
(v
2
2
−u
2
2
)
=
2
1
1(1−441)+
2
1
2(36−16)
=−200J
Impulse of Force:
I=(Δmv)
1
=1(1−21)=−20
=(Δmv)
2
=2(6−(−4))=20
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