A car of mass 300kg moving with a speed of 6 m/s. The engine applies
force so that its speed increases to 8m/s in 10 seconds. Find the force
generated by the engine.
Answers
Answer:
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A force is applied on a body of mass 20kg moving with a velocity of 40ms
−1
. The body attains a velocity of 50ms
−1
in 2 seconds. Calculate the work done to attain this velocity.
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Solution
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Force =m
t
(v−u)
=m⋅a
Displacement =
2a
(v
2
−u
2
)
Word done (W) = Force × Displacement
=m⋅a⋅
2a
(v
2
−u
2
)
W =
2
1
m(v
2
−u
2
)
W =
2
1
×20×(2500−1600)
=
2
1
×20×900
=9000J
Therefore, the work done to attain the final velocity is 9000J
Answer:
Initial speed (v1) = 6 m/s
Final speed (v2) = 8 m/s
Time taken = 10s
Acceleration = v2 - v1 / Time
= 8-6/10 = 2/10 = 0.2
Force = Mass × Acceleration = 300× 0.2
= 60 N
So , force generated by the engine is 60 Newton.
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