Question

a car of mass 400kg is moving with speed 72 m/s .calculate the braking force that can stop the car in 10 m

Answer 1

please see the image

Answer 2

Explanation:

m=400kg

u=72m/s

s=10m

v=0

${v}^{2} = {u}^{2} - 2as$

$a = {v}^{2} - {u}^{2} \div 2s = 0 - {72}^{2} \div 2 \times 10$

a=2592.2m/s

maginitude of breaking force

= f = ma

= 400*259.2

= 103.68KN