Question

A car of mass 480 kg moving at a speed of 15m/s is stopped by applying brakes in 10s. Calculate the force applied by the brakes.

Answer 1

Answer:

V=u - at (negative acceleration due to brakes)

0=15-10a

10a= 15

a=1.5m/s^(2)

F= mass × acceleration

F = 480× 1.5

F = 720 N

If it is correct

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Answer 2

QUESTION:

A car of mass 480 kg moving at a speed of 15m/s is stopped by applying brakes in 10s. Calculate the force applied by the brakes.

Explanation:

given that,

A car of mass 480 kg moving at a speed of 15m/s

here,

mass of car = 480 kg

initial velocity of car = 15 m/s

and

also given that,

the car stopped by applying brakes in 10s.

so,

final velocity = 0

time to stop car by brakes = 10 seconds

now,

we have

final velocity(v) = 0

initial velocity(u) = 15 m/s

time(t) = 10 seconds

acceleration(a) = (v - u)/t

putting the values,

a = (0 - 15)/10

a = -15/10

a = -1.5 m/s²

negation of acceleration shows the retardation

now,

by the newton's second law of motion

F = Ma

where,

F = force

M = mass = 480 kg

a = acceleration = -1.5 m/s²

now,

putting values,

F = Ma

F = (480)(-1.5)

F = -720

negation of force represents motion in the opposite direction

so,

force applied by brakes to stop the car in the velocity 15 m/s in 10 seconds

= 720 N