Question

A car of mass 480kg moving at aspeed of 54 km h-1 , is stopped by applying braks in 10s calculate the force applied by the brakes

Answer 1

m = 480 kg
u = 54 km/h = 54×5/18 = 15 m/s
v = 0
t = 10 s

a = (v-u)/t = -1.5 m/s^2

Force = ma = 480 × (-1.5) = -720N

Thus, the force applied by the breaks is 720N in the opposite direction of the motion.

(Negative sign indicates the force was applied in the opposite direction of motion)

Answer 2

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m = 480 kg

u = 54 km/h = 54×5/18 = 15 m/s

v = 0

t = 10 s

a = (v-u)/t = -1.5 m/s^2

Force = ma = 480 × (-1.5) = -720N

Thus, the force applied by the breaks is 720N in the opposite direction of the motion.

(Negative sign indicates the force was applied in the opposite direction of motion)

HOPE SO IT WILL HELP......