Physics, asked by aa189, 2 months ago

a car of mass 500 kg increases it's velocity from 40 m/s to 60m/s in 10 seconds. find the acceleration, distance travelled and force applied​

Answers

Answered by itsmeshivam1098
0

Explanation:

Given:

m= 500kg

v = 60m/s

u = 50m/s

t = 10s

acceleration = (v-u)/t

= 60-40/10

= 20/10

= 2m/s²

distance traveled = ut+1/2at²

= 40×10+1/2×2×10²

= 400+100

= 500m

force = ma

=500×2

=1000N

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