A car of mass 500 kg increases its speed from 72 km/h to 108 km/h. Find the increase in its kinetic energy?
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Explanation:
we know kinetic energy, E= (½)mv²
Given, m= 500kg
v'= 72km/h
v"= 108km/h
to find increase in kinetic energy.
now, increase in kinetic energy= E"- E'
increase in kinetic energy= (½)mv"²-(½)mv'²
= (½)m(v"²-v'²)
= (½)500(108²-72²)
= (½)500(108-72)(108+72)
= (½)500(36)(180)
=500(18)(180)
=1620000 × (10³)²/3600²
=1620000×10⁶/12960000
=162×10⁶/1296
=0.125×10⁶
increase in kinetic energy =1.25×10⁵ J.
this is the required answer.
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