Question

A car of mass 500 kg is moving with 120 km/h. What force was applied on the car through brakes such that the car came to rest after a distance of 50 m.​

Answer 1

Answer:

-10,000N

Explanation:

Speed = 120km/h

Distance = 50m / 0.05 km

Mass = 500kg

Time =?

Force =?

In this situation, we can use F =ma, where F will be negative because the force of brakes is applied in the opposite direction and that's why the car stopped.

First we need to find the time,

Speed = distance/time

120 = 0.05 /time

Time = 6 hrs.

Knowing that final velocity is 0km/h (came to rest) and initial was 120km/h, we apply F= ma

F = 500 x (0 - 120 /6

(500 x - 120)/6

- 10,000 N

Hope it helps.