Question

A car of mass 500 kg moving at 72 kilometers per hour how much force is required to stop the car within 100 meters​...
plz help me..
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Answer 1

Answer:

1000N

Step-by-step explanation:

Initial Velocity(u) :-

$72 \times \frac{1000m}{3600sec} \\ = )72 \times \frac{5}{18} \\ = )20m.sec ^{ - 1}$

Final Velocity = 0m/s

Retardation (-a) = ?

Distance (s) = 100 m

Using Third Equation Of Motion:-

${v}^{2} = {u}^{2} + 2as \\ = ) {0}^{2} = {20}^{2} + (2 \times - a \times 100) \\ = )0 = 400 + ( - 200a) \\ = )0 = 400 - 200a \\ = ) - 400 = - 200a \\ = )a = 2$

Retardation (-a)= 2m/s²

NOW:-

Force(f) = ?

Mass(m) = 500kg

Acceleration(a) = 2m/s²

$f = m \times a \\ = )500 \times 2 \\ = )1000$

Hope it helped