Question

a car of mass 500 kg taking a turn of radius hundred metre the speed of 20 metre per second is centripetal force acting on the car is​

Answer 1

Answer:

The centripeatal force required for a car (mass m) to take a sharp turn of radius r with velocity v is

F=

$\frac{m {v}^{2} }{r}$

Given m=500kg

$v=36km {h}^{( - 1)} = 36 \times \frac{18}{5} </p><p>$

=10m/s, r=50m

Hence, F=

$\frac{500 \times {10}^{2} }{50}$

=1000N