Question

a car of mass 5000kg moving with velocity 54km/h stops in 5 second . calculate the force applied by brakes​

Answer 1

Given :-

• Initial velocity, u = 54 km/h

Converting km/h to m/s :-

( Divide the value of velocity by 3.6)

Hence, Initial velocity = 15 m/s

• Time taken, t = 5 sec

• Final velocity, v = 0 m/s

• Mass of the car, m = 5000 kg

To Find :-

• The force applied by breaks

Solution :-

At first, we need to find the value of acceleration (a).

We know,

$\red{\implies \sf a=\dfrac{v-u}{t} \ m/s^{2}}$

Now, put the given values in the formula

⟼ a = ( 0 -15 ) /5

⟼ a = -3 m/s²

Hence, acceleration of the car is = -3 m/s²

According to the question :-

We are asked to find applied force.

We know,

★ Force = ma ★

Where,

m = Mass

a = Acceleration

Substituting the given values, we get

⟼ Force = 5000 × -3

⟼ Force = -15000 N

Hence, the magnitude of force applied on the car is = 15000 N.

Answer 2

Answer:

⟼ a = ( 0 -15 ) /5

⟼ a = -3 m/s²

Hence, acceleration of the car is = -3 m/s²

Force = 5000 × -3

⟼ Force = -15000 N