Question

a car of mass 500kg is moving with a speed of 10m/s on a lend road. Calculate the retarding force required to stop the car in a distance of 50mSquare​

Answer 1

Answer:

A=F/m

=3000N/500kg

=6m/s

2

Retardation is 6m/s

2

S=u

2

/(2a)

=(15m/s

2

)/(2×6m/s

2

)

Distance moved by vehicle before coming to rest is 18.75m

Answer 2

Answer:

m = 500 kg , u = 10 m/s , v = 0 , S = 50 m

v² = u² - 2rS

0² = (10)² - 2×r×50

0 = 100 - 100r

100r = 100

r = 100/100

r = 1 m/s²

Hope it is helpful...