A car of mass 500kg moving at a speed of 18 km/hr is stopped by applying breaks in 10 seconds. Calculate the force applied by the breaks.
Answers
Answered by
55
Answer:-
Given:
Mass of the car (m) = 500 kg
Initial speed / Velocity (u) = 18 km/h = 18 * 5/18 = 5 m/s
Final Velocity (v) = 0 m/s since the breaks are applied.
Time (t) = 10 s
We know that,
Force = mass * acceleration
And,
Acceleration = (v - u) / t
Hence,
Force (F) = 500 * (0 - 5) / 10
→ F = (500 * (- 5))/10
→ F = - 250 N
Hence, the force applied by the breaks is - 250 N.
Additional Information:
Force:
- Force is the push or pull of an object.
- It is a vector quantity.
- It's S.I unit is Newton (N) and C.G.S is dyne (dyn) .
- 1 N = 10⁵ dyn.
Answered by
53
GIVEN :-
- A car of mass 500kg moving at a speed of 18km/h is stopped by applying the brakes in 10 seconds .
✍️ So,
- Mass (m) = 500kg
- initial velocity (u) = 18 km/h
- time (t) = 10 second
To Find :-
- The force applied by the brakes .
CALCULATION :-
✍️ we have know that,
________________________________
✍️ To calculate acceleration, we use the below equation
✴️ Here,
- v = final velocity = 0
- u = initial velocity = 18 km/h = 5 m/s
- t = time = 10 second
[NOTE :- final velocity is zero, because brakes are applied on it . So, at last car is stopped after sometime]
✍️ Now, the force applied on it is
[NOTE :- Here force is negative, because force is applied on the opposite direction of Motion]
✍️ Therefore, the force applied by the brakes is ‘250N’ .
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