A car of mass 500kg moving with a
Velocity of 12 m brought to rest after
covering a distance of 5 metre calco force
and momentum. ( in one word answer)
Answers
Answered by
2
Explanation:
A=F/m
=3000N/500kg
=6m/s
2
Retardation is 6m/s
2
S=u
2
/(2a)
=(15m/s
2
)/(2×6m/s
2
)
Distance moved by vehicle before coming to rest is 18.75m
Hence,
ans 18.75m
Answered by
5
Answer:
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