Question

A car of mass 50kg accelerate from rest at 1m/s,what is the total distance covered in 1min

Answer 1

Mass of the car = 50kg

Acceleration of the car = 1 $m/s^{2}$

Time = 1 min

Acceleration = (v-u)/t   [was at rest ]

1 = (v-0)/1

1 = v/1

v = 1

Now, From $v^{2} = u^{2} + 2as$

$1^{2} = 0^{2} + 2*1*s\\ 1 = 0 + 2s\\2s = 1\\s = 1/2 m$

Hope it helps you !!!!!