A car of mass 800 kg is travelling with a velocity of 20m/s. When brakes are applied , it stops after travelling a distance of 8 meters. Find retardation and retarding force
Answers
Answered by
11
Given m=800kg, v(initial)=20m/s and v(final)=0 m/s
S=8m
From the equation of motion,
v^2-u^2=2as
(0)^2 - (20)^2 = 2(a)(8)
-400=2(a)(8)
=> a= -25m/s^2(retardation)
Retarding force (F)=MA
=800x-25
= -20000N
I hope that it is helpful
S=8m
From the equation of motion,
v^2-u^2=2as
(0)^2 - (20)^2 = 2(a)(8)
-400=2(a)(8)
=> a= -25m/s^2(retardation)
Retarding force (F)=MA
=800x-25
= -20000N
I hope that it is helpful
Answered by
1
Answer:
20000N
Explanation:
v²-u²=2as
0²-20²=2*a*8
-400=16a
a=400/16
a= -25 m/s or 25 m/s
f=ma
f=800*25
=20000N
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