a car of mass 800 kilogram is travelling with a velocity of 20 metre per second.when brakes are applied it stops after travelling a distance of 8 metre find retardation and retarding force.
pls answer correctly if wrong I will report the answer
Answers
Answered by
1
Explanation:
s=8
m=800
u=20
v=0
v^2-u^2=2as
-400=2×a×8
-400÷16=a
a=-25
retardation is -25 and is aways negative
Answered by
1
Answer:
retardation (a) = -25 m/s^2
retarding force (F) = -20,000 N
Explanation:
Given - mass (m) = 800 kg
initial velocity (u) = 20 m/s
distance (x) = 8 m
final velocity (v) = 0 m/s
i) To find retardation -
v^2 = u^2 + 2ax
(0)^2 = (20)^2 + 2(a)(8)
0 = 400 + 16a
-400 = 16a
a = -400/16
a = -25 m/s^2
ii) To find retarding force -
F = ma
F = 800 x (-25)
F = -20,000 N
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